Skip to main content

Timeline for Eigenvectors of Kronecker Product

Current License: CC BY-SA 4.0

4 events
when toggle format what by license comment
Dec 1, 2019 at 18:23 comment added alesia if both matrices are diagonalizable, their tensor product does have a basis of eigenvectors of the form you indicate
Dec 1, 2019 at 17:55 comment added Henrique de Oliveira Ha! Good point. Now I feel silly. I'll see if there is a different way of phrasing the question...
Dec 1, 2019 at 17:54 vote accept Henrique de Oliveira
Dec 1, 2019 at 17:49 history answered Federico Poloni CC BY-SA 4.0