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Nov 21, 2019 at 17:45 comment added Student Added! Thanks for the comment. At least point I'm not sure if I want those too. But since the picture comes from TQFT, I'd suppose to! My original intention was to get some pointers to useful references, but it hasn't been done yet, I should dig more into my question and make it more precise.
Nov 21, 2019 at 17:41 comment added მამუკა ჯიბლაძე @Student Could you please add to the question what exactly do you mean by compatibility? For example, $\mathbb C[G]$ also has a right $G$-action and satisfies $(ab)g=a(bg)$ and $(ag)b=a(gb)$, do you want these too?
Nov 21, 2019 at 17:38 comment added Student Hmm yes it is not natural. The instance in my mind comes from Witten-Dijkgraaf 2d-TQFT, where representations are assigned to points. It seems to me that the algebra structure of $\mathbb{C}[G]$ plays an important role.. so I'd like to know more examples.. or even a classification if any.
Nov 21, 2019 at 16:33 comment added Tom De Medts Oh, I see, I should have looked at your example more carefully. (I also see now that you want associative unital algebras, which is also not what I had in mind.) I think that your definition of "compatible" is less natural (because the elements of $G$ do not induce automorphisms of this algebra structure), but of course your question makes perfect sense.
Nov 21, 2019 at 14:33 comment added Student Hmm.. I did not mention explicitly, but as my example $\mathbb{C}[G]$ suggests, the algebra is compatible in the way that $g(ab) = (ga)b$. In your answer, I suppose you mean $Hom_G(V\otimes V,V)$. However, $G$ acts on $V\otimes V$ by $g(v\otimes w) = gv\otimes gw$.
Nov 21, 2019 at 9:17 history answered Tom De Medts CC BY-SA 4.0