Timeline for Cup Product with Ample Line Bundles
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
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Nov 21, 2019 at 7:49 | vote | accept | Winnie_XP | ||
Nov 21, 2019 at 6:15 | review | Close votes | |||
Nov 22, 2019 at 12:22 | |||||
Nov 21, 2019 at 5:53 | answer | added | abx | timeline score: 4 | |
Nov 21, 2019 at 3:12 | comment | added | Winnie_XP | @BalazsElek I see, thanks. Let me edit my post for more details. | |
Nov 21, 2019 at 3:12 | history | edited | Winnie_XP | CC BY-SA 4.0 |
added 13 characters in body
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Nov 21, 2019 at 3:08 | comment | added | Balazs Elek | Yes, my comment only answers your question if $2k<n$. | |
Nov 21, 2019 at 3:03 | comment | added | Winnie_XP | @BalazsElek Dear Balaza, thanks for your reply. I am a bit confused here. Say n=dim X, and k=n-1. HL says that $H^2\to H^{2n-2}$ is isomorphism, but I am actually consider $\cup c_1(L)\colon H^{2n-2}\to H^2n}$ here ? | |
Nov 21, 2019 at 2:58 | comment | added | Balazs Elek | If $\alpha\in H^{2k}(X\mathbb{Q})$ and $2k<n$, where $n=\dim_\mathbb{C}(X)$ then this is a consequence of the Hard Lefschetz Theorem, which says that if $L$ is ample, then the map $(c_1(L))^{r} \cup -: H^{n-r}(X,\mathbb{Q}) \to H^{n+r}(X,\mathbb{Q})$ is an isomorphism. | |
Nov 21, 2019 at 2:04 | history | asked | Winnie_XP | CC BY-SA 4.0 |