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Nov 20, 2019 at 18:30 comment added Marty @IlyaBogdanov: Thank you for getting straight to the point :) Yes, I think you're right. And I've updated the question significantly to give a precise conjecture. Your comment suggests something deeper than a bit of real analysis is needed, if my conjecture is indeed true.
Nov 20, 2019 at 18:26 history edited Marty CC BY-SA 4.0
Big update after comment by I.B.
Nov 20, 2019 at 8:37 comment added Ilya Bogdanov Did you try it on a rational function whose integral is zero? Say, $1/(x+1)-\ln 2$? Intuitively, this should not become $0$ in finitely many steps, as the poles will not cancel...
Nov 19, 2019 at 22:51 history asked Marty CC BY-SA 4.0