Timeline for Transformations preserving the number of distinct eigenvalues
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
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Nov 13, 2019 at 21:41 | history | edited | Ludwig | CC BY-SA 4.0 |
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Nov 13, 2019 at 18:11 | history | edited | Ludwig | CC BY-SA 4.0 |
I rewrote the entire question in order to improve clarity
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Nov 13, 2019 at 16:38 | history | edited | Ludwig | CC BY-SA 4.0 |
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Nov 13, 2019 at 6:55 | history | edited | Ludwig | CC BY-SA 4.0 |
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Nov 13, 2019 at 6:32 | comment | added | Ludwig | @ChristianRemling yes it is not symmetric (there was a typo). However $g(A,t)$ is similar to a symmetric matrix. | |
Nov 13, 2019 at 6:26 | history | edited | Ludwig | CC BY-SA 4.0 |
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Nov 12, 2019 at 23:52 | comment | added | Christian Remling | I don't think $g(A,t)$ is still symmetric. | |
Nov 12, 2019 at 21:42 | comment | added | Ludwig | @IlyaBogdanov: yes thanks! I fixed the typo. I enumerate the eigenvalues in an increasing order: $\lambda_1$ is the smallest eigenvalue of $g(A,t)$. Basically, I wonder whether there are no crossings between the eigenvalues. | |
Nov 12, 2019 at 21:39 | history | edited | Ludwig | CC BY-SA 4.0 |
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Nov 12, 2019 at 20:58 | comment | added | Ilya Bogdanov | 1) Did you forget to take the inverse when defining $\Sigma(t)$? 2) How do you enumerate the eigenvalues? What is $\lambda_1$? Do you merely ask whether teo eigenvalues may become equal? | |
Nov 12, 2019 at 20:29 | history | asked | Ludwig | CC BY-SA 4.0 |