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Nov 13, 2019 at 15:28 vote accept David E Speyer
Nov 12, 2019 at 16:50 comment added David E Speyer Thanks! This looks nice. I may try this out next time I teach our honors calculus on manifolds course.
Nov 12, 2019 at 16:10 comment added Tobias Diez Sure, this particular statement follows from the rank theorem. If I understood @David E Speyer correctly, he wanted to have a general theorem/treatment of various applications of the inverse function theorem, and this is what this abstract normal theorem provides. The singular part $f_s$ is of course only important if you work with submersions/constant rank maps.
Nov 12, 2019 at 15:51 comment added Ben McKay You might just use the usual rank theorem to say that $(x_1,\dots,x_{n-1},f)$ are local coordinates, so can just write them as $(x_1,\dots,x_{n-1},x_n)$, and then $(x_n=0)$ has coordinates $x_1,\dots,x_{n-1}$. I don't see why you need to worry about $f_s$, and without $f_s$, this is just the usual rank theorem.
Nov 12, 2019 at 14:53 history answered Tobias Diez CC BY-SA 4.0