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Nov 12, 2019 at 8:56 comment added Anixx When speaking about divergent integrals one should interpret $x$ not as an arbitrary variable but as a special symbol meaning the identity function $\operatorname{id}$
Nov 12, 2019 at 6:54 comment added Anixx For instance if you apply variable change to $\int_0^\infty dx$ you can get arbitrary results.
Nov 12, 2019 at 6:37 comment added Anixx No, I simply think the kind of variable change that you used is not applicable to divergent integrals. Rather the results produced by distribution theory and hpyperfunction theory are correct.
Nov 11, 2019 at 15:23 history answered Jacques Carette CC BY-SA 4.0