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Aug 8, 2023 at 6:07 comment added Pietro Majer One can multiply $\Gamma(x)$ e.g. by $\exp(\sin(2\pi x))$ and get a solution of the same functional equation, I think everybody knows that.
Jan 15, 2023 at 7:02 history edited Martin Sleziak CC BY-SA 4.0
fixed the Wikipedia link
Feb 9, 2021 at 9:59 comment added José Hdz. Stgo. The magic words here are "Bohr-Mollerup theorem"...
Mar 14, 2017 at 19:07 comment added Rellek It is the only one that is log convex (ie, $\log(\Gamma(x))$ is a convex function).
Oct 18, 2015 at 12:45 comment added Arnaud Chéritat I think I remember reading it is the only one that is convex over $(0,+\infty)$ or some similar condition.
Aug 4, 2010 at 22:29 history answered Andrey Rekalo CC BY-SA 2.5