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Aug 29, 2021 at 7:50 vote accept Isaac
Nov 9, 2019 at 23:35 comment added LSpice @DerekHolt, thanks!
Nov 9, 2019 at 22:53 comment added Derek Holt @LSpice It's known as the ATLAS notation for group structures defined in the Atlas of Finite Groups. Yes, $2^8$ denotes an elementary abelian group. The cyclic group of that order would be denoted by $256$. You can also use $[256]$ to denote a group of that order with unspecified structure.
Nov 9, 2019 at 14:52 comment added LSpice Where are these various kinds of notations for extensions (the colon and dot, as well as, e.g., whether $2^8$ means, say, the elementary Abelian 2-group of order $2^8$, as I assume, or a cyclic group of order $2^8$, or whatever else) defined?
Nov 9, 2019 at 14:50 history edited LSpice CC BY-SA 4.0
TeX fixes
Nov 9, 2019 at 13:35 comment added David Roberts @Isaac en.wikipedia.org/wiki/Outer_automorphism_group See also the top of the second page here: projecteuclid.org/download/pdf_1/euclid.bbms/1102715061. See the classic reference jstor.org/stable/1969174 and the discussion and references at encyclopediaofmath.org/index.php/Extension_of_a_group
Nov 9, 2019 at 13:12 answer added Derek Holt timeline score: 4
Nov 9, 2019 at 9:20 history edited Dima Pasechnik CC BY-SA 4.0
texification and no greetings
Nov 9, 2019 at 8:41 history edited Isaac CC BY-SA 4.0
added 62 characters in body
Nov 9, 2019 at 8:22 comment added Derek Holt It is not possible to answer this question without further information. There is more than one isomorphism type of group that fits that description.
Nov 9, 2019 at 5:15 comment added Isaac Can you explain "an outer action of H".
Nov 9, 2019 at 4:29 comment added David Roberts You might wish to consider the general case of $G.H$ — $G$ is a normal subgroup of $G.H$, so $G.H$ acts by conjugation. From this you can achieve an outer action of $H$.
Nov 9, 2019 at 3:23 history edited Isaac CC BY-SA 4.0
edited body; edited title
Nov 8, 2019 at 19:59 comment added Derek Holt Also the title of your post does not agree with the body.
Nov 8, 2019 at 18:37 comment added verret Assuming this is usual Atlas notation, $2^8$ does not act on $(2^7:Sp(6,2))$, since the latter is a quotient, not a normal subgroup.
Nov 8, 2019 at 17:34 history edited YCor
edited tags
Nov 8, 2019 at 17:00 review Close votes
Nov 16, 2019 at 3:05
Nov 8, 2019 at 16:05 review First posts
Nov 8, 2019 at 16:41
Nov 8, 2019 at 16:01 history asked Isaac CC BY-SA 4.0