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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
Nov 11, 2019 at 21:22 vote accept Akerbeltz
S Nov 11, 2019 at 21:17 history bounty ended Akerbeltz
S Nov 11, 2019 at 21:17 history notice removed Akerbeltz
Nov 11, 2019 at 16:30 comment added Student Have you drawn some simple examples ($p=1,2$) after reading @Hatcher's answer below? I think the the consideration of $(-\times I)$ could be quite helpful.
Nov 11, 2019 at 14:54 history edited Akerbeltz CC BY-SA 4.0
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Nov 11, 2019 at 0:36 answer added Allen Hatcher timeline score: 14
S Nov 9, 2019 at 20:16 history bounty started Akerbeltz
S Nov 9, 2019 at 20:16 history notice added Akerbeltz Authoritative reference needed
Nov 8, 2019 at 19:10 comment added Akerbeltz @CharlesRezk I already did some work in drawing some simple cases. However this didn't solve the problem.
Nov 8, 2019 at 17:10 comment added Charles Rezk In particular, the formula for the boundary of the cone is just saying: the boundary of a cone is the union of the "hat" part of the cone and the "base" of the cone.
Nov 8, 2019 at 17:09 comment added Charles Rezk I recommend computing $h$ for a single simplex $\sigma$ of low dimension (e.g., 0, 1, 2). This might give you a better idea of what is goin on.
Nov 7, 2019 at 21:10 comment added Akerbeltz If $\mathcal{U}$ is an oper cover of a topological space $X$, $C_\bullet^\mathcal{U}(X)$ represents the chain complex of \mathcal{U}-small chains in $X$, whose elements are chains such that the image of each of its simplices is contained in some element of the cover $\mathcal{U}$. $H_p^\mathcal{U}(X)$ is just the homology of such complex.
Nov 7, 2019 at 21:02 comment added Arun Debray Sorry for my confusion, but what are $C_*^{\mathcal U}(X)$ and $H_p^{\mathcal U}(X)$? I am not familiar with that notation.
Nov 7, 2019 at 20:27 comment added Wlod AA Perhaps, this is about the acyclic carriers.
Nov 7, 2019 at 20:05 history asked Akerbeltz CC BY-SA 4.0