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Nov 7, 2019 at 3:25 history edited user128095 CC BY-SA 4.0
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Nov 7, 2019 at 3:19 comment added user128095 @SamZbarsky Thanks for pointing out that.
Nov 7, 2019 at 3:12 comment added Sam Zbarsky It seems unlikely, barring stupid answers like the trivial topology. For any function $g=T(f,v)$ in the image of $T$, we have that $|g(1,0,\ldots,0)-g(0,\ldots,0)|+|g(0,1,0,\ldots,0)-g(0,\ldots,0)|\le |v_1|+|v_2|\le\sqrt{2}$. After taking convex combinations, we get $|F(1,0,\ldots,0)-F(0,\ldots,0)|+|F(0,1,0,\ldots,0)-F(0,\ldots,0)|\le\sqrt{2}$. However, for the function $h(x)=|x|$, this quantity is 2. It's possible you can fix this by only trying approximating, e.g. $Lip_{\alpha(d)}$ functions for some $\alpha(d)$. I'm not sure what the right dependence on $d$ is.
Nov 7, 2019 at 3:10 history edited user128095 CC BY-SA 4.0
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Nov 7, 2019 at 3:04 history edited LSpice CC BY-SA 4.0
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Nov 7, 2019 at 2:57 history asked user128095 CC BY-SA 4.0