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Sep 8, 2021 at 7:06 comment added Joel David Hamkins Yes, it is a (parametric) bi-interpretation of theories.
Sep 7, 2021 at 15:56 comment added Oscar Cunningham @JoelDavidHamkins When you mention bi-interpretation above, do you mean that it's a biinterpretation of the theories, or merely of the models? I've asked a question about this here.
Nov 8, 2019 at 11:00 vote accept user221330
Nov 6, 2019 at 23:25 comment added Joel David Hamkins Ah, you are right. I have edited.
Nov 6, 2019 at 23:09 history edited Joel David Hamkins CC BY-SA 4.0
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Nov 6, 2019 at 22:40 comment added Alex Kruckman There's a little bit of a hitch with QE, because the theory of $\langle\mathbb{R},+,\cdot,0,1\rangle$ does not have QE! You have to throw in the ordering $\leq$. So for example the formula $\exists x\, (x = \overline{x}\land x^2 = y)$ which defines the non-negative real numbers in $\mathbb{C}$ is not equivalent to a quantifier-free formula. On the other hand, model-completeness transfers from $\mathbb{R}$ to $\mathbb{C}$ with conjugation for exactly the reason you give: the interpretation involves only quantifier-free formulas.
Nov 6, 2019 at 21:19 history edited Joel David Hamkins CC BY-SA 4.0
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Nov 6, 2019 at 21:10 history answered Joel David Hamkins CC BY-SA 4.0