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Nov 5, 2019 at 17:52 comment added sigmatau This argument would also hold for general $\sigma$ as long as $||\sigma||^2_{\infty} = O(N)$, right?
Nov 5, 2019 at 7:07 history undeleted Carlo Beenakker
Nov 5, 2019 at 7:06 history edited Carlo Beenakker CC BY-SA 4.0
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Nov 5, 2019 at 7:03 history deleted Carlo Beenakker via Vote
Nov 5, 2019 at 6:58 history answered Carlo Beenakker CC BY-SA 4.0