Timeline for A question about complements in a group
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 3, 2019 at 8:04 | vote | accept | W4cc0 | ||
| Nov 2, 2019 at 20:53 | answer | added | YCor | timeline score: 4 | |
| Nov 2, 2019 at 18:24 | comment | added | W4cc0 | @verret second paragraph, but anyway this property is known (but I do not have a proof of it) to be inherited by factor groups of periodic groups satisfying it | |
| Nov 2, 2019 at 18:22 | comment | added | verret | Every factor group of which $G$? An arbitrary $G$ as in the first paragraph, or the more specific one in the second paragraph? | |
| Nov 2, 2019 at 17:23 | comment | added | YCor | I've edited to clarify, feel free to revert if you don't like it. Also it would be helpful to provide the reference to the Russian paper. | |
| Nov 2, 2019 at 17:22 | history | edited | YCor | CC BY-SA 4.0 |
clarified
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| Nov 2, 2019 at 17:19 | history | edited | W4cc0 | CC BY-SA 4.0 |
deleted 1 character in body
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| Nov 2, 2019 at 17:16 | comment | added | W4cc0 | @YCor yes "cartesian product"="unrestricted direct product". The sentence is: "For every cyclic subgroup of prime order there is a complement". This sentence should be satisfied in every factor group. | |
| Nov 2, 2019 at 17:09 | comment | added | YCor | What do you mean by "this property holds all factors groups"? the previous sentence does not refer to any quotient group. Maybe you mean the claim that every normal subgroup has a "complement"? | |
| Nov 2, 2019 at 17:05 | comment | added | YCor | I think "cartesian product" is a word used mostly in Russian to mean "unrestricted direct product". I'm rather familiar to using "cartesian" to mean the setwise product, and "direct" referring to the choice of law (a semidirect product $A\ltimes B$ is another group law on the cartesian product $A\times B$). | |
| Nov 2, 2019 at 16:21 | history | asked | W4cc0 | CC BY-SA 4.0 |