Timeline for Two-variable singular perturbation analysis
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Nov 1, 2019 at 17:18 | comment | added | tom | I agree that it is obvious, but how does one develop a perturbation expression in which the zeroth order approximation is $x_0=\delta/(\varepsilon+\delta)$ and the first order approximation gives the error term $\mathcal{O}(\varepsilon)$ to order $\mathcal{O}(\varepsilon^2)$. I don't know how to choose an expansion which gives this particular approximation -__- | |
| Nov 1, 2019 at 9:03 | history | edited | YCor | CC BY-SA 4.0 |
removed capitals, added tag
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| Nov 1, 2019 at 2:30 | comment | added | Christian Remling | There's nothing to show really: Comparing your desired statement with the first equation, we see that we must show that $\epsilon\delta x^2 = O(\epsilon\delta)$ or, equivalently, that $x^2=O(1)$, which you assumed. | |
| Nov 1, 2019 at 0:41 | history | asked | tom | CC BY-SA 4.0 |