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Nov 1, 2019 at 0:46 history edited Luis Ferroni CC BY-SA 4.0
Undo last change due to a mistake.
Nov 1, 2019 at 0:33 history edited Luis Ferroni CC BY-SA 4.0
I added a stronger statement that may be (or not) easier to prove than the original one.
Oct 31, 2019 at 16:33 comment added Luis Ferroni Hi Rene, indeed in the original post it already says it is a repost. It happens that the difficulty of the question I think fits better here rather than MSE.
Oct 31, 2019 at 15:46 comment added René Gy This is repost from math.stackexchange
Oct 30, 2019 at 15:35 comment added Luis Ferroni I forgot to add, to avoid carrying denominators, $S(k,n,m)$ is multiplied by $(n-1)!$.
Oct 30, 2019 at 15:25 comment added Luis Ferroni Let $P_{k,n}(t)$ the coefficient of $x^{kt}$ in $(1+x+\ldots+x^t)^n$. You can easily prove this is indeed a polynomial. The number $S(k,n,m)$ would be the coefficient of $t^m$ in $P_{k,n}(t)$.
Oct 30, 2019 at 15:07 comment added Fedor Petrov Would you please write the polynomials also?
Oct 30, 2019 at 14:55 review First posts
Oct 30, 2019 at 15:43
Oct 30, 2019 at 14:50 history asked Luis Ferroni CC BY-SA 4.0