Timeline for Positivity of a finite sum involving Stirling numbers of the first kind
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
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Nov 1, 2019 at 0:46 | history | edited | Luis Ferroni | CC BY-SA 4.0 |
Undo last change due to a mistake.
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Nov 1, 2019 at 0:33 | history | edited | Luis Ferroni | CC BY-SA 4.0 |
I added a stronger statement that may be (or not) easier to prove than the original one.
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Oct 31, 2019 at 16:33 | comment | added | Luis Ferroni | Hi Rene, indeed in the original post it already says it is a repost. It happens that the difficulty of the question I think fits better here rather than MSE. | |
Oct 31, 2019 at 15:46 | comment | added | René Gy | This is repost from math.stackexchange | |
Oct 30, 2019 at 15:35 | comment | added | Luis Ferroni | I forgot to add, to avoid carrying denominators, $S(k,n,m)$ is multiplied by $(n-1)!$. | |
Oct 30, 2019 at 15:25 | comment | added | Luis Ferroni | Let $P_{k,n}(t)$ the coefficient of $x^{kt}$ in $(1+x+\ldots+x^t)^n$. You can easily prove this is indeed a polynomial. The number $S(k,n,m)$ would be the coefficient of $t^m$ in $P_{k,n}(t)$. | |
Oct 30, 2019 at 15:07 | comment | added | Fedor Petrov | Would you please write the polynomials also? | |
Oct 30, 2019 at 14:55 | review | First posts | |||
Oct 30, 2019 at 15:43 | |||||
Oct 30, 2019 at 14:50 | history | asked | Luis Ferroni | CC BY-SA 4.0 |