Skip to main content
4 events
when toggle format what by license comment
Oct 30, 2019 at 14:04 vote accept ABIM
Oct 30, 2019 at 14:00 answer added Iosif Pinelis timeline score: 1
Oct 30, 2019 at 11:21 comment added ABIM Since $\nu$ is a probability measure then $K_n\triangleq \nu^{-1}[\frac1{2}^n,\frac1{2}^n-\frac1{2}^{n+1}]$ is $\nu$-measureable and of $\nu$ measure $\frac1{2^n}$. Since $\nu$ is an *outer-*regular Borel measure then there are open subsets $U_n^k$ satisfying - $\nu(U_n^k)\leq \nu(U_n^{k+1})\mapsto \nu(K_n)$ - $K_n\subseteq U_n^k$. Some more work probably shows the result...
Oct 30, 2019 at 10:51 history asked ABIM CC BY-SA 4.0