Timeline for Group of parallelizations of $M^3$ finitely generated?
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
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Dec 2, 2019 at 16:58 | vote | accept | user101010 | ||
Nov 4, 2019 at 18:16 | answer | added | mme | timeline score: 2 | |
Oct 30, 2019 at 17:54 | comment | added | Igor Belegradek | The cover $S^3\to SO(3)$ is principal bundle with fiber $\mathbb Z_2$, so it is classified by maps into $B\mathbb Z_2=RP^\infty$. | |
Oct 30, 2019 at 17:27 | history | edited | user101010 | CC BY-SA 4.0 |
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Oct 30, 2019 at 17:27 | comment | added | user101010 | @IgorBelegradek Oh yes - orientable - thanks. What is the classifying map for 2-fold covers? | |
Oct 30, 2019 at 16:05 | comment | added | Igor Belegradek | For $TM$ to be trivial $M$ must be orientable. The classifying map for the 2-fold covering $S^3\to SO(3)$ induces an exact sequence of pointed sets $[M, S^3]\to [M, SO(3)]\to [M, RP^\infty]$. If $M$ is closed oriented, the degree identifies $[M, S^3]$ and $H^3(M)$, and also $[M, RP^\infty]=H^1(M;\mathbb Z_2)$ which are finitely generated abelian groups. It remains to see if the maps in the exact sequence are group homomorphisms. | |
Oct 30, 2019 at 11:00 | comment | added | YCor | The last sentence would better fit as a separate question. | |
Oct 30, 2019 at 10:57 | history | edited | YCor |
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Oct 30, 2019 at 9:49 | history | asked | user101010 | CC BY-SA 4.0 |