Timeline for Is the map sending a continuous function to its period measurable?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 30, 2019 at 1:57 | comment | added | R.. GitHub STOP HELPING ICE | @BK: $\inf \{ t \in \mathbb{R}^+ | (\forall x \in \mathbb{R}) f(x+t) = f(x) \}$ | |
| Oct 30, 2019 at 0:57 | comment | added | B K | Is it clear that $p$ is well-defined? To me it is not completely obvious that an arbitrary continuous function is either non-periodic or has a unique period. | |
| Oct 29, 2019 at 20:53 | history | became hot network question | |||
| Oct 29, 2019 at 13:40 | comment | added | Giuseppe Negro | One way of extracting the period of a function is taking the Fourier transform, see for example this signal processing post. You get a Dirac comb, the width of which is inversely proportional to the period. This operation is continuous, because the compact-open convergence implies convergence as a tempered distribution. However, I don't know if this is useful for you. | |
| Oct 29, 2019 at 13:10 | vote | accept | sayantankhan | ||
| Oct 29, 2019 at 13:05 | answer | added | Mateusz Kwaśnicki | timeline score: 21 | |
| Oct 29, 2019 at 12:44 | history | asked | sayantankhan | CC BY-SA 4.0 |