Timeline for How to prove $(\phi-1)(\phi-2)...(\phi-p) = \sqrt{5} + p\left(\frac{1}{2}+A\sqrt{5}\right) \bmod p^2$?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 31, 2019 at 1:45 | comment | added | ueir | I'm interested in the formula which you obtained from this argument. Do you find anything for $\frac{T+2}{2p} \bmod p$ part? For $\sum_{i=0}^{(p-1)/2} \frac{i}{1+i-i^2} \bmod p$ part, it seems some rule exist (link). | |
| Oct 29, 2019 at 13:09 | comment | added | Fedor Petrov | @ueir well, some formula is obtained from this argument, but not very nice. | |
| Oct 29, 2019 at 5:41 | comment | added | ueir | Thank you. Is it possible to get the formula for $A$? | |
| Oct 27, 2019 at 14:22 | vote | accept | ueir | ||
| Oct 27, 2019 at 12:29 | comment | added | Fedor Petrov | @WhatsUp thank you, fixed | |
| Oct 27, 2019 at 12:28 | history | edited | Fedor Petrov | CC BY-SA 4.0 |
edited body
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| Oct 27, 2019 at 12:27 | comment | added | WhatsUp | There's a $\mod 5$ which I believe should be $\mod p$. Nice answer! | |
| Oct 27, 2019 at 9:18 | history | answered | Fedor Petrov | CC BY-SA 4.0 |