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Oct 29, 2019 at 0:29 vote accept Diego Reyes
Oct 27, 2019 at 7:30 comment added YCor @LSpice $\mathbf{Q}$ is the traditional printed notation for rational numbers. Anyway, your edit is useful.
Oct 27, 2019 at 0:34 comment added LSpice I changed $\mathbb Q$, which I think is unusual notation for anything but the rational numbers, to $\mathbf Q$ $\mathbf Q$; of course you can make it anything else you like. I also deleted the text-with-emoticon at the end, which doesn't belong; and replaced the $\mathbf{math-mode fakery}$ $\mathbf{math-mode fakery}$ by MathJax **MathJax**.
Oct 27, 2019 at 0:33 history edited LSpice CC BY-SA 4.0
Hilbert cube, not rationals; and other proofreading
Oct 26, 2019 at 22:00 answer added Henno Brandsma timeline score: 0
Oct 22, 2019 at 1:00 review Close votes
Nov 5, 2019 at 3:05
Oct 21, 2019 at 20:50 comment added Taras Banakh The set $\{0\}\times[0,1]^\omega$ is nowhere dense but not a $Z$-set in $[-1,1]\times[0,1]^\omega$. It is even not a $Z_1$-set in $[-1,1]\times[0,1]^\omega$ (which means that some map of the interval stably intersects $\{0\}\times[0,1]^\omega$).
Oct 21, 2019 at 18:43 comment added Diego Reyes Hi Yemon Choi. This question arose from a postgraduate course that I am currently studying. I must find the solution to the problem but I can't find the solution so I am looking for suggestions to try other ways.
Oct 21, 2019 at 18:35 review First posts
Oct 22, 2019 at 0:42
Oct 21, 2019 at 18:33 comment added Yemon Choi The phrasing of your question makes it sound like a question that you were asked to answer. If this is not the case, could you say a bit more about how this problem arose in the context of your research?
Oct 21, 2019 at 18:30 history asked Diego Reyes CC BY-SA 4.0