Timeline for A closed subset $B$ of the Hilbert cube such that $\operatorname{Int}(B) = \emptyset$ and $B$ is not a z-set
Current License: CC BY-SA 4.0
11 events
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Oct 29, 2019 at 0:29 | vote | accept | Diego Reyes | ||
Oct 27, 2019 at 7:30 | comment | added | YCor | @LSpice $\mathbf{Q}$ is the traditional printed notation for rational numbers. Anyway, your edit is useful. | |
Oct 27, 2019 at 0:34 | comment | added | LSpice |
I changed $\mathbb Q$, which I think is unusual notation for anything but the rational numbers, to $\mathbf Q$ $\mathbf Q$ ; of course you can make it anything else you like. I also deleted the text-with-emoticon at the end, which doesn't belong; and replaced the $\mathbf{math-mode fakery}$ $\mathbf{math-mode fakery}$ by MathJax **MathJax** .
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Oct 27, 2019 at 0:33 | history | edited | LSpice | CC BY-SA 4.0 |
Hilbert cube, not rationals; and other proofreading
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Oct 26, 2019 at 22:00 | answer | added | Henno Brandsma | timeline score: 0 | |
Oct 22, 2019 at 1:00 | review | Close votes | |||
Nov 5, 2019 at 3:05 | |||||
Oct 21, 2019 at 20:50 | comment | added | Taras Banakh | The set $\{0\}\times[0,1]^\omega$ is nowhere dense but not a $Z$-set in $[-1,1]\times[0,1]^\omega$. It is even not a $Z_1$-set in $[-1,1]\times[0,1]^\omega$ (which means that some map of the interval stably intersects $\{0\}\times[0,1]^\omega$). | |
Oct 21, 2019 at 18:43 | comment | added | Diego Reyes | Hi Yemon Choi. This question arose from a postgraduate course that I am currently studying. I must find the solution to the problem but I can't find the solution so I am looking for suggestions to try other ways. | |
Oct 21, 2019 at 18:35 | review | First posts | |||
Oct 22, 2019 at 0:42 | |||||
Oct 21, 2019 at 18:33 | comment | added | Yemon Choi | The phrasing of your question makes it sound like a question that you were asked to answer. If this is not the case, could you say a bit more about how this problem arose in the context of your research? | |
Oct 21, 2019 at 18:30 | history | asked | Diego Reyes | CC BY-SA 4.0 |