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Timeline for Size of sets with complete double

Current License: CC BY-SA 4.0

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Oct 21, 2019 at 13:25 comment added RobPratt $m(100) \in [22,25]$. Best so far is $S= \{0,1,3,4,6,10,13,15,21,29,37,45,53,61,69,77,84,85,90,94,95,96,97,99,100\}$.
Oct 21, 2019 at 3:59 comment added Hailong Dao After reading some literature I start to suspect that $\lim s(n)/\sqrt{n}$ might be larger than $2$. Is it possible to compute $s(100)$? Thanks.
Oct 20, 2019 at 15:50 history edited RobPratt CC BY-SA 4.0
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Oct 20, 2019 at 6:06 comment added Hailong Dao Ah, that's clever. While you are at it, does the program tell you how many solutions for each $n$?
Oct 20, 2019 at 5:45 history answered RobPratt CC BY-SA 4.0