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Oct 15, 2019 at 13:10 history edited YCor
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Oct 15, 2019 at 13:07 comment added YCor This is widely known as (smooth) diffeomorphism group. It's true. One way to prove this is to observe that $g$ preserves a Riemannian metric, and then use that every Riemannian manifold that is homeomorphic to $\mathbf{R}$ is smoothly isometric to an interval of $\mathbf{R}$. By the existence of an orientation-reversing involution, it has to be smoothly isometric to $\mathbf{R}$ or $]-1,1[$. One easily concludes.
Oct 15, 2019 at 13:00 review First posts
Oct 15, 2019 at 13:57
Oct 15, 2019 at 12:58 history asked Anon E. Mous CC BY-SA 4.0