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Aug 4, 2010 at 7:45 vote accept TmobiusX
Aug 4, 2010 at 1:50 comment added TmobiusX Does the equality hold when M is not finite?
Aug 3, 2010 at 9:25 comment added Angelo To the OP: I think this should be proved in any book that discusses dimensions of modules. In case as Martin says it is a very easy exercise. To Dylan: the dimension of the spectrum of a ring A is the Krull dimension of A, and the definition for modules is a useful generalization. It can also be interpreted as the Krull dimension of the ring modulo the annihilator of the module (I am always referring to finite modules over noetherian rings).
Aug 3, 2010 at 8:45 comment added Martin Brandenburg $dim(X \cup Y) = max(dim(X),dim(Y))$ is a an easy exercise in general topology.
Aug 3, 2010 at 8:04 comment added TmobiusX Is there a reference for this result? Thanks!
Aug 3, 2010 at 7:50 comment added Dylan Wilson Thanks! Is it called the "Krull dimension" though? That's what confused me...
Aug 3, 2010 at 7:35 history answered Angelo CC BY-SA 2.5