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Oct 11, 2019 at 7:53 comment added Kurisuto Asutora No, this is not applicable here, since the trigonometric polynomial is not a sum of independent random variables. There is an analogue of Bernstein's inequality, but only if the sequence $(n_k)_k$ grows very quickly, e.g. exponentially. See for example Kac, M.: On the distribution of values of sums of the type $\sum f(2^k t).$ Ann. of Math. (2) 47 (1946), 33–49.
Oct 11, 2019 at 7:43 vote accept Kurisuto Asutora
Oct 11, 2019 at 2:42 answer added Terry Tao timeline score: 9
Oct 10, 2019 at 17:16 comment added pseudocydonia You should be able to do better using some version of the Azuma-Hoeffding inequality? Or Bernstein's inequality?
Oct 10, 2019 at 14:41 history asked Kurisuto Asutora CC BY-SA 4.0