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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
Oct 7, 2019 at 3:23 comment added Yemon Choi @MattF. To be fair, it seemed to me that the original question also asked/allowed for negative answers: "If not can you explain why Nash theorem is less useful and powerful than expected?"
Oct 7, 2019 at 1:21 history edited Zurab Silagadze CC BY-SA 4.0
a doubtfull link removed
Oct 6, 2019 at 21:25 comment added user44143 The quote is nice but it doesn’t answer the question. Saying that Nash’s theorem is not part of Riemannian geometry, not much to do with classical PDE, and shows no significant influence of the geometry on the imbeddings — all that does not suggest why the theorem is useful in a positive sense.
Oct 6, 2019 at 21:05 history edited Zurab Silagadze CC BY-SA 4.0
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Oct 6, 2019 at 20:59 history answered Zurab Silagadze CC BY-SA 4.0