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Oct 7, 2019 at 15:55 history closed YCor
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Emil Jeřábek
David Handelman
Neil Hoffman
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Oct 4, 2019 at 6:35 review Close votes
Oct 7, 2019 at 15:55
Oct 4, 2019 at 6:23 vote accept Dominic van der Zypen
Oct 4, 2019 at 6:16 comment added YCor Obviously not. For instance if the chain has no maximum and each $C$ is infinite cyclic, then the union is not cyclic (the union cannot be finitely generated). For example $\mathbf{Z}[1/2]=\bigcup\frac1{2^n}\mathbf{Z}$ and $\mathbf{Q}=\bigcup\frac1{n!}\mathbf{Z}$.
Oct 4, 2019 at 6:13 answer added James E Hanson timeline score: 6
Oct 4, 2019 at 6:06 history asked Dominic van der Zypen CC BY-SA 4.0