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Oct 3, 2019 at 5:43 review Suggested edits
Oct 3, 2019 at 10:31
Oct 2, 2019 at 19:28 comment added Ali Yes you are correct, and that is why heuristically I only expect the finite speed of propagation to hold in the region that I defined. It could still easily be wrong
Oct 2, 2019 at 19:23 comment added Willie Wong The principal part of your operator is not hyperbolic. Using $\sigma, \tau, \xi$ for the dual variables, the principal symbol is $P_2(\sigma,\tau,\xi) = - \tau^2 + \xi^2$. This is not hyperbolic in the $\tau$ direction as for any $\sigma \neq 0$, the mapping $\tau \mapsto P_2(\sigma,\tau,0)$ has a double root.
Oct 2, 2019 at 18:07 history asked Ali CC BY-SA 4.0