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Dec 13, 2022 at 14:29 vote accept Gro-Tsen
Oct 16, 2019 at 12:24 comment added KP Hart @Robert Furber: I'm old school
Oct 2, 2019 at 14:02 comment added Robert Furber Much as I esteem your expertise in general topology, I don't know why you insist "there is no $\beta X$". Some of us use $\beta X$ for the Gelfand spectrum of $C_b(X)$. This is the left adjoint to the forgetful functor from compact Hausdorff spaces to topological spaces. When restricted to completely regular spaces it agrees with any other construction of $\beta X$, such as Stone's or Čech's, as it has the same universal property. The map $X \rightarrow \beta X$ is then injective iff $X$ is functionally Hausdorff and an embedding iff $X$ is Tychonoff.
Oct 2, 2019 at 12:10 history answered KP Hart CC BY-SA 4.0