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Oct 15, 2019 at 15:46 vote accept Clark Kimberling
Oct 1, 2019 at 21:50 answer added Ilya Bogdanov timeline score: 3
Oct 1, 2019 at 20:40 history edited Clark Kimberling CC BY-SA 4.0
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Oct 1, 2019 at 18:52 comment added Aeryk I don't see how $B_c$ depends on $c$ at all...
Oct 1, 2019 at 18:06 comment added René Gy @Aeryk, shouldn't it be $B_c(n)$ instead of $b_n$ in your equation?
Oct 1, 2019 at 17:42 comment added Aeryk I feel like something's not right in this question. It seems that by definition $A_1(n)-A_0(n) = (b_{2n}+b_{4n}+1)-(b_{2n}+b_{4n}+0) = 1$. Yet this does not agree with the initial values of $A_0$ and $A_1$. So either I'm missing something or maybe there's been a typo.
Oct 1, 2019 at 15:32 history asked Clark Kimberling CC BY-SA 4.0