Timeline for Any homogeneous symplectomorphism of cotangent bundle $\dot{T}^*M=T^*M-0_M$ preserves the canonical Liouville form?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 4, 2019 at 1:17 | vote | accept | SoYu | ||
| Oct 4, 2019 at 1:06 | comment | added | SoYu | @sanette: Oh, thanks. I corrected. | |
| Oct 4, 2019 at 1:05 | history | edited | SoYu | CC BY-SA 4.0 |
edited title
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| Oct 1, 2019 at 20:15 | comment | added | sanette | you mean 'cotangent' instead of 'tangent' | |
| Oct 1, 2019 at 20:12 | answer | added | sanette | timeline score: 4 | |
| Oct 1, 2019 at 1:46 | comment | added | SoYu | @Bertram Arnold: I mean that $\phi$ is $\mathbb{R}^{\times}$-equivariant with respect to the action and I don't know whether $\alpha_M$ is $\mathbb{R}^{\times}$-equivariant. | |
| Sep 30, 2019 at 19:00 | comment | added | abx | @Bertram Arnold: You mean that $\phi$ is equivariant with..., not $\alpha_M$ (otherwise you are right of course). | |
| Sep 30, 2019 at 9:00 | comment | added | Bertram Arnold | If you mean that $\alpha_M$ is equivariant with respect to the $\mathbb R^\times$-action of rescaling the fibers, this follows from $\alpha_M = \iota_{E}\omega$, where $E$ is the generator of this action and therefore preserved by any equivariant map. | |
| Sep 30, 2019 at 8:47 | history | asked | SoYu | CC BY-SA 4.0 |