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Jun 15, 2020 at 11:35 comment added Yuxiao Xie So, as of today, is this conjecture considered solved? It seems that the paper of Brendle only deals with dimensions $\geq12$.
Oct 15, 2019 at 3:18 comment added Entao Zhao Thanks, I didn't know this. Also, the preprint arxiv.org/abs/1909.12265v1 was revised. The result is not as strong as in version 1.
Sep 30, 2019 at 12:04 comment added Thomas Richard The answer to the question asked was already answered by Brendle's work. In fact if $M$ is PIC, compact and simply connected, then it is homemorphic to $S^n$. Now $S^n$ does not contain incompressible space forms (it is a topological assumption), so we can apply Brendle's result.
Sep 30, 2019 at 8:10 review Late answers
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Sep 30, 2019 at 7:55 review First posts
Sep 30, 2019 at 8:02
Sep 30, 2019 at 7:53 history answered Entao Zhao CC BY-SA 4.0