Timeline for Number of cycles under a certain action on Z/nZ [closed]
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
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Sep 29, 2019 at 1:58 | history | closed |
Greg Martin user44191 Neil Hoffman David Handelman Yemon Choi |
Not suitable for this site | |
Sep 27, 2019 at 18:22 | comment | added | Rory | @WhatsUp: Thanks, sorry for that. | |
Sep 27, 2019 at 18:22 | comment | added | Rory | @TomDeMedts: Yes, precisely, that was just an error in description on my part. | |
Sep 27, 2019 at 16:40 | review | Close votes | |||
Sep 29, 2019 at 1:58 | |||||
Sep 27, 2019 at 15:56 | comment | added | WhatsUp | A (friendly) warning: the question is not about research level mathematics and normally it is more suitable for the "mathematics" site. People are being kind, so it still gets answered instead of put on hold. | |
Sep 27, 2019 at 12:24 | answer | added | Geoff Robinson | timeline score: 3 | |
Sep 27, 2019 at 9:57 | comment | added | Tom De Medts | @YCor: I think the OP means neither of the two, but just the set $\mathbb{Z}/n\mathbb{Z}$ with the action given by multiplication by an invertible element $k$ modulo $n$. | |
Sep 27, 2019 at 9:25 | comment | added | YCor | I'm not sure to understand what is "the multiplicative group $Z/nZ$", as this is an additive group with an multiplication that does not make a group. Maybe you mean a multiplicative group that is cyclic of order $n$ ($\mu_n$ is a better notation), or the group of invertibles in $Z/nZ$. | |
Sep 27, 2019 at 9:20 | comment | added | LeechLattice | How are the cycles represented in order to tell what cycle $m$ belongs to? | |
Sep 27, 2019 at 9:05 | review | First posts | |||
Sep 27, 2019 at 10:00 | |||||
Sep 27, 2019 at 9:04 | history | asked | Rory | CC BY-SA 4.0 |