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Sep 29, 2019 at 1:58 history closed Greg Martin
user44191
Neil Hoffman
David Handelman
Yemon Choi
Not suitable for this site
Sep 27, 2019 at 18:22 comment added Rory @WhatsUp: Thanks, sorry for that.
Sep 27, 2019 at 18:22 comment added Rory @TomDeMedts: Yes, precisely, that was just an error in description on my part.
Sep 27, 2019 at 16:40 review Close votes
Sep 29, 2019 at 1:58
Sep 27, 2019 at 15:56 comment added WhatsUp A (friendly) warning: the question is not about research level mathematics and normally it is more suitable for the "mathematics" site. People are being kind, so it still gets answered instead of put on hold.
Sep 27, 2019 at 12:24 answer added Geoff Robinson timeline score: 3
Sep 27, 2019 at 9:57 comment added Tom De Medts @YCor: I think the OP means neither of the two, but just the set $\mathbb{Z}/n\mathbb{Z}$ with the action given by multiplication by an invertible element $k$ modulo $n$.
Sep 27, 2019 at 9:25 comment added YCor I'm not sure to understand what is "the multiplicative group $Z/nZ$", as this is an additive group with an multiplication that does not make a group. Maybe you mean a multiplicative group that is cyclic of order $n$ ($\mu_n$ is a better notation), or the group of invertibles in $Z/nZ$.
Sep 27, 2019 at 9:20 comment added LeechLattice How are the cycles represented in order to tell what cycle $m$ belongs to?
Sep 27, 2019 at 9:05 review First posts
Sep 27, 2019 at 10:00
Sep 27, 2019 at 9:04 history asked Rory CC BY-SA 4.0