Timeline for Is $H^i(\mathcal{M}_g,F)$ necessarily finite dimensional for a coherent sheaf $F$?
Current License: CC BY-SA 4.0
11 events
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| Sep 30, 2019 at 0:04 | vote | accept | CommunityBot | ||
| Sep 29, 2019 at 16:13 | answer | added | Angelo | timeline score: 6 | |
| Sep 29, 2019 at 15:25 | history | edited | user39380 | CC BY-SA 4.0 |
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| Sep 29, 2019 at 15:22 | comment | added | user39380 | @Angelo Maybe I am missing something elementary... would you explain a little bit more? Thanks! | |
| Sep 29, 2019 at 15:16 | comment | added | Angelo | Why should that be true? In fact, a quasiprojective variety $X$ with the property that $\mathrm{H}^i(X, F)$ is finite-dimensional for all locally free sheaves $F$ is projective. | |
| Sep 29, 2019 at 14:26 | history | edited | user39380 | CC BY-SA 4.0 |
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| Sep 29, 2019 at 14:13 | history | edited | user39380 | CC BY-SA 4.0 |
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| Sep 29, 2019 at 14:02 | comment | added | user39380 | @ulrich Oh, thanks! Taking normalization looks good enough to show $H^0(M_g,\mathcal{O}_{M_g})=\mathbb{C}$...maybe I should modify the question | |
| Sep 29, 2019 at 12:18 | comment | added | naf | Why is replacing $\widetilde{M}_g$ with its normalisation not good enough? | |
| Sep 29, 2019 at 1:41 | history | edited | user39380 | CC BY-SA 4.0 |
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| Sep 27, 2019 at 2:00 | history | asked | user39380 | CC BY-SA 4.0 |