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Timeline for Closed form for unusual recurrence

Current License: CC BY-SA 4.0

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Sep 27, 2019 at 0:24 comment added Max Alekseyev Substituting $q_k(n,m)=\frac{p_k(n,m)}{k!(n-1)!m!}$ results in a simpler recurrence: $$q_k(n,m) = \sum_{s=0}^{n-1} (m+1)q_{k-1}(s+1,m+1) + q_{k-1}(m+1,s).$$
Sep 26, 2019 at 23:01 history edited YCor
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Sep 26, 2019 at 22:56 comment added Konstantinos Kanakoglou Some reference?
Sep 26, 2019 at 22:34 history asked user514787 CC BY-SA 4.0