Timeline for Closed form for unusual recurrence
Current License: CC BY-SA 4.0
4 events
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Sep 27, 2019 at 0:24 | comment | added | Max Alekseyev | Substituting $q_k(n,m)=\frac{p_k(n,m)}{k!(n-1)!m!}$ results in a simpler recurrence: $$q_k(n,m) = \sum_{s=0}^{n-1} (m+1)q_{k-1}(s+1,m+1) + q_{k-1}(m+1,s).$$ | |
Sep 26, 2019 at 23:01 | history | edited | YCor |
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Sep 26, 2019 at 22:56 | comment | added | Konstantinos Kanakoglou | Some reference? | |
Sep 26, 2019 at 22:34 | history | asked | user514787 | CC BY-SA 4.0 |