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Sep 27, 2019 at 1:46 comment added R W Sure - still thank you for making clear this distinction - as otherwise your answer could be misinterpreted.
Sep 26, 2019 at 21:39 history edited Iosif Pinelis CC BY-SA 4.0
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Sep 26, 2019 at 21:21 comment added Iosif Pinelis @RW : You are of course right, it would be incorrect to say "the conditional measures are well-defined for all $\alpha\in[0,1]$. Of course, I did not say anything like that. Rather, I said "you can let $\mathbf P_\pi [\cdot \mid x_i=\alpha]:=\nu_i(\alpha,\cdot)$ for all $\alpha\in[0,1]$." I also said "a regular conditional probability distribution", not "the regular conditional probability distribution". To make it quite clear, I have now also added a remark about the nonuniqueness of a regular conditional probability distribution.
Sep 26, 2019 at 21:17 history edited Iosif Pinelis CC BY-SA 4.0
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Sep 26, 2019 at 18:06 comment added R W It is completely misleading to claim that the conditional measures are well-defined for all $\alpha\in[0,1]$.
Sep 26, 2019 at 17:05 vote accept Vojtěch Kovařík
Sep 26, 2019 at 16:44 history edited Iosif Pinelis CC BY-SA 4.0
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Sep 26, 2019 at 15:49 history answered Iosif Pinelis CC BY-SA 4.0