Timeline for Is it a known property of positive integers $n> 2 $ that one must have $n < \mathrm{rad}(n(n-1)(n-2))$?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 1, 2023 at 1:31 | vote | accept | Đào Thanh Oai | ||
| Jun 14, 2020 at 11:30 | answer | added | Adam P. Goucher | timeline score: 5 | |
| S Jun 14, 2020 at 8:43 | history | suggested | user142929 | CC BY-SA 4.0 |
I've added explicitely the definition of radical of an integer as companion of the linked Wikipedia, see also A007947 from the OEIS. Added the tags (inequality) and (analytic-number-theory).
|
| Jun 14, 2020 at 8:01 | review | Suggested edits | |||
| S Jun 14, 2020 at 8:43 | |||||
| Sep 27, 2019 at 1:21 | comment | added | Đào Thanh Oai | @Wojowu Thank You so much, In general case $rad(ABC)>min(A,B)$ is false | |
| Sep 26, 2019 at 19:04 | history | edited | YCor | CC BY-SA 4.0 |
formatting, removed duplicate
|
| S Sep 26, 2019 at 18:16 | history | suggested | JoshuaZ | CC BY-SA 4.0 |
clean up phrasing. Based on tag also adding explicit question about if previously conjectured.
|
| Sep 26, 2019 at 17:21 | review | Suggested edits | |||
| S Sep 26, 2019 at 18:16 | |||||
| Sep 26, 2019 at 16:14 | comment | added | Wojowu | Let me note that since we have $n+(n-2)=2(n-1)$, if $n$ is odd the abc conjecture gives $rad(n(n-1)(n-2))^{1+\varepsilon}>2(n-1)>n$ for large $n$. We get similar bound after dividing by $2$ if $n$ is even. | |
| Sep 26, 2019 at 15:46 | history | edited | Đào Thanh Oai | CC BY-SA 4.0 |
edited body
|
| Sep 26, 2019 at 15:41 | history | asked | Đào Thanh Oai | CC BY-SA 4.0 |