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Sep 26, 2019 at 2:11 history edited Myshkin CC BY-SA 4.0
added 10 characters in body
Sep 25, 2019 at 17:12 vote accept Myshkin
Sep 25, 2019 at 15:15 comment added mike you seem to really mean $P(X_i=-\infty)>0$ , then the prob you want is bounded by the probability that you haven't seen -infinity yet, which is of the right form. . But then of course E(X) = $-\inf$.
Sep 25, 2019 at 14:27 answer added Iosif Pinelis timeline score: 4
Sep 25, 2019 at 14:15 review Close votes
Oct 4, 2019 at 3:05
Sep 25, 2019 at 10:33 history asked Myshkin CC BY-SA 4.0