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Sep 30, 2019 at 7:54 comment added user146384 @Benighted Sure, you'll have to replace the $\mathbb{Z}^2$ by something else, like $d \mathbb{Z}^2$, and the index will no longer be an integer.
Sep 25, 2019 at 16:18 comment added Benighted This is great, thanks a lot! Maybe I'm just not looking in the right places, but it would be nice if this was remarked in the literature somewhere. By the way, you say a "congruence subgroup of this kind." Is something like, say, $\varphi(d\tau, z)$ possibly a Jacobi form for some more exotic subgroup?
Sep 25, 2019 at 16:15 vote accept Benighted
Sep 25, 2019 at 10:15 review First posts
Sep 25, 2019 at 12:40
Sep 25, 2019 at 10:14 history answered user146384 CC BY-SA 4.0