The inequality as follows like the Erdős–Mordell inequality, I found a year ago, and sent the inequality to some people but I no have a proof until now.

Let $ABC$ be a triangle with the centroid $G$, $D$ is the point in the plane. Let $GEF$ is a cevian triangle of $D$. How can prove that:

$$DA+DB+DC \le 2(DG+DE+DF)+3DG$$

Ono's inequality is true for acute triangle but false with general triangles. The inequality as follows is false with general triangls but I think it true with acute triangle (follows answer by Fedor Petrov)

The inequality as follows like the Erdős–Mordell inequality, I found a year ago, and sent the inequality to some people but I no have a proof until now.

Let $ABC$ be acute triangle (replaced general triangle by acute triangle following Fedor Petrov's answer) with the centroid $G$, $D$ is the point in the plane. Let $EFH$ is a cevian triangle of $D$. How can prove that:

$$DA+DB+DC \le 2(DE+DF+DH)+3DG$$

The inequality as follows like the Erdős–Mordell inequality, I found a year ago, and sent the inequality to some people but I no have a proof until now.

Let $ABC$ be a triangle with the centroid $G$, $D$ is the point in the plane. Let $GEF$ is a cevian triangle of $D$. How can prove that:

$$DA+DB+DC \le 2(DG+DE+DF)+3DG$$

The inequality as follows like the Erdős–Mordell inequality, I found a year ago, and sent the inequality to some people but I no have a proof until now.

Let $ABC$ be a triangle with the centroid $G$, $D$ is the point in the plane. Let $GEF$ is a cevian triangle of $D$. How can prove that:

$$DA+DB+DC \le 2(DG+DE+DF)+3DG$$