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Sep 24, 2019 at 11:00 vote accept Mikhail Borovoi
Sep 24, 2019 at 5:24 vote accept Mikhail Borovoi
Sep 24, 2019 at 5:30
Sep 24, 2019 at 4:00 answer added YCor timeline score: 5
Sep 23, 2019 at 19:11 comment added Mikhail Borovoi However, some other people (say, Dmitri Akhiezer), work with a pair $(G,\sigma)$, where $G$ is a complex semisimple group, and $\sigma$ is an anti-holomorphic involution. I would like to be sure that this is the same, at least for semisimple groups.
Sep 23, 2019 at 19:07 comment added Mikhail Borovoi Actually, I work with anti-regular involutions. My working definition of a real algebraic group is: a pair $(G, \sigma)$, where $G$ is a complex algebraic group and $\sigma$ is an anti-regular involution.
Sep 23, 2019 at 19:03 comment added Mikhail Borovoi @YCor: No, I do not know that.
Sep 23, 2019 at 19:00 comment added YCor Do you already know whether all bi-holomorphic group automorphisms are regular? do you know the answer to your question when $G$ is abelian?
Sep 23, 2019 at 18:49 history asked Mikhail Borovoi CC BY-SA 4.0