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Dec 8, 2019 at 6:04 history edited Ali Taghavi
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Sep 19, 2019 at 5:37 comment added reuns See en.wikipedia.org/wiki/Dirichlet_series#Abscissa_of_convergence if $\sum_{n=1}^\infty\frac{a(n)}{n^{s_0}}$ converges then $$\sum_{n=1}^\infty\frac{a(n)}{n^s}= \lim_{N\to \infty} N^{s_0-s} (\sum_{n=1}^N a(n) n^{-s_0}) + \sum_{n=1}^{N-1} (\sum_{m=1}^n a(m)m^{-s_0}) (n^{s_0-s}-(n+1)^{s_0-s})$$ converges and is analytic for $\Re(s) > \Re(s_0)$ and where it is meromorphic it has no poles on $\Re(s_0)$. The converse is very specific to $\zeta(s)$ and follows from the same Tauberian theorems as in the proof of the PNT.
Sep 18, 2019 at 23:15 history rollback Yemon Choi
Rollback to Revision 2
S Sep 18, 2019 at 22:41 history suggested user142929 CC BY-SA 4.0
Feel free to reject my edit: improved minor aspects of the post and added the tags (analytic-continuation) and (dirichlet-series)
Sep 18, 2019 at 21:36 review Suggested edits
S Sep 18, 2019 at 22:41
Sep 18, 2019 at 17:29 answer added Wojowu timeline score: 7
Sep 18, 2019 at 17:04 answer added David E Speyer timeline score: 3
Sep 18, 2019 at 15:36 comment added Conrad where did you hear that?
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Sep 30, 2019 at 3:05
Sep 18, 2019 at 14:17 history edited Rafik1 CC BY-SA 4.0
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Sep 18, 2019 at 14:11 history asked Rafik1 CC BY-SA 4.0