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Sep 19, 2019 at 18:59 vote accept Filip
Sep 18, 2019 at 13:56 answer added Danny Ruberman timeline score: 9
Sep 18, 2019 at 11:21 comment added Thomas Rot I don't know Filip92.
Sep 18, 2019 at 10:15 history edited Filip CC BY-SA 4.0
I add the condition that manifold is simply connected
Sep 18, 2019 at 10:14 comment added Filip Hmm, I see. I will put an additional condition that the manifold is simply connected. Is it then true?
Sep 18, 2019 at 9:10 comment added Thomas Rot I do not know anything about Kähler manifolds, but if one only assumes that the manifold is symplectic this is very far from true. Gompf has shown that there exist, for any finitely presented group $G$, a closed symplectic four manifold $M$ with fundamental group $G$. Now take a perfect group $G$, then $H_1(M)=H_3(M)=0$, but it will not admit a Morse function with only even indices.
Sep 17, 2019 at 18:39 history edited Filip
edited tags
Sep 17, 2019 at 18:15 history asked Filip CC BY-SA 4.0