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Sep 15, 2019 at 6:34 vote accept user142929
Sep 15, 2019 at 6:30 comment added user142929 Many thanks for your answer.
Sep 15, 2019 at 4:30 comment added Michael Engelhardt Choosing $f(x)=x$ and substituting $x=\sin^2 t$ yields something similar (roughly speaking, swap the first and second sequences in the argument of the hypergeometric function, while shifting the odd sequence in the numerator up by 2).
Sep 15, 2019 at 3:27 history answered Michael Engelhardt CC BY-SA 4.0