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Sean Eberhard
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No. Take $\alpha=g$, a group element, and consider a non-trivial one dimensional representation of the cyclic group generated by $g$. If $G$ has no abelainabelian quotient then you're doomed.

No. Take $\alpha=g$, a group element, and consider a non-trivial one dimensional representation of the cyclic group generated by $g$. If $G$ has no abelain quotient then you're doomed.

No. Take $\alpha=g$, a group element, and consider a non-trivial one dimensional representation of the cyclic group generated by $g$. If $G$ has no abelian quotient then you're doomed.

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Uri Bader
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No. Take $\alpha=g$, a group element, and consider a non-trivial one dimensional representation of the cyclic group generated by $g$. If $G$ has no abelain quotient then you're doomed.