Skip to main content
6 events
when toggle format what by license comment
Sep 13, 2019 at 22:54 comment added Willie Wong (In the above, $\sin(i|x|)$ should obviously be $\sin(|x|)$, the $i$ is spurious.) As to the $\cos(|x|)$ part, I don't have a copy of Stein's Beijing lecture notes handy, so I cannot check whether he has a more applicable version of the Stein-Tomas theorem there.
Sep 13, 2019 at 22:50 comment added Willie Wong The version of Stein-Tomas I remember would give exactly the control you write, except with $\exp$ replaced by $\sin$. You use the fact that $\sin(i|x|)/ 4\pi|x|$ is the Fourier transform of the surface measure of the unit sphere, so if $T$ is the mapping that sends a function $f$ on $\mathbb{R}^3$ to the surface measure on the sphere given by $\hat{f} \mu$ where $\mu$ is the standard surface area measure, then the $\sin$ version of your inequality would be estimating $T^*T f$. Since Stein-Tomas says $T$ is bounded from $L^{4/3}$ to $L^2$, so is the mapping for $T^*T$.
S Sep 13, 2019 at 16:11 history rollback Tao
Rollback to Revision 1 - Edit approval overridden by post owner or moderator
Sep 13, 2019 at 14:09 history suggested Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing: norm sign scaling+ $exp\, \to\, \exp$.
Sep 13, 2019 at 12:38 review Suggested edits
S Sep 13, 2019 at 16:11
Sep 13, 2019 at 12:10 history asked Tao CC BY-SA 4.0