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Sep 13, 2019 at 6:54 comment added user136400 @Ozawa Sir, can you please elaborate the reason why this example will work?
Sep 13, 2019 at 0:48 comment added Narutaka OZAWA It's obviously possible for $G=F_\infty$. Also, e.g., if $G$ embeds densely into a compact group $K$, then $G\curvearrowright L^\infty(K)$ is an example.
Sep 12, 2019 at 10:23 history edited user136400 CC BY-SA 4.0
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Sep 12, 2019 at 10:09 history edited user136400 CC BY-SA 4.0
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Sep 12, 2019 at 9:51 history edited YCor CC BY-SA 4.0
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Sep 12, 2019 at 9:50 comment added YCor A group is said to be $C^*$-simple if its reduced $C^*$-algebra is simple (every proper quotient is reduced to $\{0\}$). This also means that whenever a nonzero unitary representation is weakly contained in the regular representation, then it weakly contains the regular representation.
Sep 12, 2019 at 9:24 comment added Matthew Daws Some questions which might improve the question: what is a $C^*$-simple group? What is $\|\cdot\|_2$ (asked because you have placed no restriction on your von Neumann algebra $M$).
Sep 12, 2019 at 9:08 history edited user136400
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Sep 12, 2019 at 8:31 history asked user136400 CC BY-SA 4.0