Timeline for Irreducible components of quotients of Cohen-Macaulay rings of the "correct" dimension
Current License: CC BY-SA 2.5
4 events
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Aug 1, 2010 at 13:47 | history | edited | damiano | CC BY-SA 2.5 |
modified so that it answers the question
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Aug 1, 2010 at 7:58 | comment | added | Hailong Dao | Otherwise, we can just take $I=(a,b)$, and it will be the same as your example. | |
Aug 1, 2010 at 7:55 | comment | added | Hailong Dao | Hi damiano, I have to make the ideal $I$ codimension 1 because the OP assumes that $I$ does not have codimension $n$! | |
Aug 1, 2010 at 7:40 | history | answered | damiano | CC BY-SA 2.5 |