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Oct 15, 2022 at 20:24 comment added paul garrett On a compact manifold, the resolvent of the Laplacian is a compact operator...
Jul 13, 2022 at 9:37 comment added Sebastian Hebold The Laplacian is an unbounded operator, considered as an operator from some L2 space of forms to itself. Therefore, its spectrum will also be unbounded.
Jul 9, 2022 at 1:55 comment added QGravity @SebastianHebold what is the meaning of "the eigenvalues accumulate only at infinity"? isn't the spectrum of Laplacian bounded?
Sep 11, 2019 at 9:12 comment added Sebastian Hebold Oh thanks. I guess I'm the donkey, that wasn't able to remove the last parts of the link to get to the website :D.
Sep 10, 2019 at 23:48 comment added Nate Eldredge The book is The Laplacian on a Riemannian Manifold by Steven Rosenberg. It's linked from his web page math.bu.edu/people/sr.
Sep 10, 2019 at 17:40 history edited Sebastian Hebold CC BY-SA 4.0
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Sep 10, 2019 at 17:35 review First posts
Sep 10, 2019 at 18:55
Sep 10, 2019 at 17:34 history answered Sebastian Hebold CC BY-SA 4.0