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Sep 18, 2019 at 2:36 vote accept Joseph Vandehey
Sep 12, 2019 at 11:11 answer added LeechLattice timeline score: 4
Sep 11, 2019 at 2:49 comment added Joseph Vandehey Unfortunately the $\epsilon$'s I am working with are around $.4$ to $.6$, so that bound isn't helpful.
Sep 10, 2019 at 5:54 comment added Seva Since we have $r_A(n)≥2$ for all $n\in 2A$ with very few exceptions, your $E(A)$ is essentially equal to the sum of $r_A(n)−2$, which is $$\sum_{n\in 2A} r_A(n)−2\sum_{n\in 2A}1=|A|^2−2|2A|>(1+\varepsilon)^2N−4N; $$ does this answer your question if $\varepsilon$ is not too small?
Sep 9, 2019 at 5:18 history asked Joseph Vandehey CC BY-SA 4.0